## Statement

difficulty An electric car to scale moves in a circular track describing a uniform circular motion. If the center of the track is placed in the position (0, 0) m determine:

a) The position vector when it is in position (3, 4) m.
b) The radius of the circular trajectory it describes.
c) Its angular position when it is in the position (3, 4) m.

## Solution

Data

Center of the circular trajectory: C (0,0) m

Point belonging to the circular trajectory: A (3,4) m

Resolution

a) The position vector $\stackrel{\to }{r}$ of a body is a vector that goes from the origin of coordinates to the position of said body. So, to calculate the vector we must calculate the vector that goes from the Center C to point A.

b) To calculate the radio of the circumference we must calculate the distance from the origin C to any of the points that make up the trajectory. Since we know one of those points (A) and we already have the position vector for said point, the magnitude of said vector is equal to the value of R. Therefore:

c) Considering that we know the position vector of point A (3.4):

$\stackrel{\to }{r}=x·\stackrel{\to }{i}+y·\stackrel{\to }{j}=R·\mathrm{cos}\left(\phi \right)·\stackrel{\to }{i}+R·\mathrm{sin}\left(\phi \right)·\stackrel{\to }{j}$

We have two equations to calculate the angular position:

Using the first one:

## Formulas worksheet

These are the main formulas that you must know to solve this exercise. If you are not clear about their meaning, we recommend you to check the theory in the corresponding sections. Furthermore, you will find in them, under the Formulas tab, the codes that will allow you to integrate these equations in external programs like Word or Mathematica.

Formulas
Related sections
$\stackrel{\to }{r}=x\stackrel{\to }{i}+y\stackrel{\to }{j}$
$\left|\stackrel{\to }{r}\right|=\sqrt{{x}^{2}+{y}^{2}}$
$\stackrel{\to }{r}=x·\stackrel{\to }{i}+y·\stackrel{\to }{j}=R·\mathrm{cos}\left(\phi \right)·\stackrel{\to }{i}+R·\mathrm{sin}\left(\phi \right)·\stackrel{\to }{j}$